![]() ![]() ![]() These are angles that had their vertices at the center of. Given such a triangulation, the analog of the trapezoid rule is: X(28.3) f(x,y)dx dyarea(T)(average value offat the three vertices ofT). Previously, when you worked with angles in a triangle, you were mainly working with central angles. So that this angle and this angle makes 60 plus 1 20 will be equal 218. , vn), is a decomposition into non-overlapping triangles, such that all thevi, and no other points, appear as vertices of those trian-gles. So therefore half angle of 60 will be 30 each. Maybe we can see that this angle should be 30 degrees because in equilateral triangle, that angle should be 60 degrees to match 60 60 60 because the total angle is 60 times three should be equal to 1 80. Therefore it means that this is our that is our this would be these three will be X. He said the points A, B and C here and this point center point is all. ![]() Um because it's an equilateral triangle, it would then mean have redrawn this figure. Example 3: Find the area of the major segment of a circle if the area of the corresponding minor segment is 62 sq. Therefore, the area of the segment is 22 sq. So let's look at how we can prove R squared equals two X squared by three firstly. Area of the segment area of the sector- area of the triangle. Um but before that we need to first show that r squared equals two X squared by three. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is the. They're asking us to express the circumstances of the circle as a function of the length X. In this problem, an equilateral triangle is inscribed in a circle of radius R. ![]()
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